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slava [35]
3 years ago
6

George has $15. He tries to buy a movie ticket ($9.00), a pretzel ($2.65), a drink ($1.35), and two veggie cups ($1.74 each) but

he does not have enough money Look at the numerical expression George used
15 - 9+ 2.65 + 1.35 + 2(1.74)
Can you help him determine why he does not have enough money? ​
Mathematics
2 answers:
Zinaida [17]3 years ago
7 0

Answer: he needs to buy one less veggie cup

Step-by-step explanation:

Nimfa-mama [501]3 years ago
6 0

Answer:

Sample Response: George did not put parentheses around the total snack amount to be subtracted from his $15. He needed to total the purchases and then subtract that amount from $15.

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Gap sells jeans that cost $21.00 for a selling price of $29.95. The percent of markup based on cost is
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If Gap sells jeans that cost $21.00 for selling price of $29.95. The percent of markup based on cost is approximately 43%. The markup in price is exactly $8.95.
3 0
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Please help worth lot of points
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Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911
nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

\lambda=\dfrac{1}{2}

(a) What is the expected number of 911 calls in one hour?

\lambda=\dfrac{1}{2}\times 60=30

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

\lambda=\dfrac{1}{2}\times 5=2.5

Number of calls = 3

So, P(X=3) is given by

P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820

Hence, a) 30, b) 0.2138, c) 0.0820

4 0
3 years ago
Find the GCF of 6x^7 and 15x^3?
LekaFEV [45]
I believe the answer is 3x^3

since 3 is the greatest common factor for the whole number and both have at least x to the third
5 0
3 years ago
A bag contains 40 marbles. The probability of selecting a red marble at random is 1/5. How many red marbles are in the bag?
goblinko [34]

Answer:

8 red marbles.

Step-by-step explanation:

All together we have 40 marbles. The fraction of marbles that are red is 1/5 which means that we should divide the total number of marbles, which is 40 by the denominator ( Bottom number of fraction ) 5 so that we get the number of groups that have 1 red marble in them. In this case we have 8 groups.

40/5=8

You always divide by the denominator ( Bottom number of fraction ) first and then you multiply your answer by the numerator ( Top number of fraction ) .

If each group has 1 red marble in it and we have 8 groups, it means that we have 8 red marbles in the bag.

1 * 8 = 8 red marbles in the bag

If the numerator (number above the fraction line) was more than one, then this would mean that we have more than 1 marble in each group of marbles.

Example:

If we had 3/5 we would have 3 marbles in each group of marbles. This means that instead of doing 1 * 8 we would have to do 3 * 8 = 24. We would have 24 red marbles in the bag.

Easy and quick way if you do not need the explanation:

Another way we could do this is by simply multiplying the fraction ( 1/5 ) by the total number of marbles ( 40 ). This would still give us an answer of 8 red marbles in the bag. 40/5=8, 8*1=8

7 0
3 years ago
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