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Free_Kalibri [48]
3 years ago
9

What happens when energy is added to a liquid without changing its phase

Physics
1 answer:
djverab [1.8K]3 years ago
5 0

the mole of the substance will boiling or freezing point ,

all of it melt or boiled,but the temperature won't change

water boil at 212°F (100°C)

energy remove and it will be ice

if energy is added to the matter

hope you understand!!!!!!!!!!!

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What happens as water cools
Ksivusya [100]

Answer:

it decreases in size

Explanation:

The reason why this happens is simply just condensation. unlike when water is boiling, that is evaporating

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What is the spreading out of light into different colors called?
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The answer is dispersion!
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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined t
poizon [28]
Based on the information given: 
The vertical velocity is 13.9 * sin (35°) = 7.97 m/s
The horizontal velocity is 13.9 * cos (35°) = 11.39 m/s

  First, let's see how long the ball will be in the air, given its initial vertical velocity of 7.97 m/s. To do this, let's see when the vertical velocity equals zero (when the ball reaches the vertical peak of its trajectory, or the moment just before the ball starts to come down). Remember that acceleration due to gravity is -9.8 /s²
v(t) = vi - at
0 = 7.97 + -9.8 * t     Subtract 7.97 from both sides
-7.97 = -9.8 * t          Divide both sides by -9.8
t = .8135
The height at this point was:
h(t) = vi (t) + (1/2) a *t²
h(t) = 7.97 (.8135) + (1/2) (-9.8) (.8135²)
h(t) = 6.48 - 3.24
h(t) = 3.24m

How long until the ball came down? How long does it take a ball to fall 3.24 meters, with an initial vertical velocity of 0?
3.24 = 0 - (1/2) (9.8) (t²)           Divide both sides by (9.8/2)
t² = .66                                     Take the square root of both sides
t = .835
/
The ball took about the same amount of time, .8 seconds, to come down as it did to come up. Total time ball was in air: .813 + .835 = 1.648

The balled traveled for 1.648 seconds at a constant horizontal speed (11.39 m/s) before coming down. How far did it travel?
1.648 * 11.39 = 18.77 m

What is the change given this new angle, compared to the 25° angle?
18.77 - 15.1 = 3.67

How do the two angles differ in terms of the general path of the ball? In the 25° angle, the ball was kicked at a shallower angle (kind of like a line drive hit in baseball), and traveled with a higher horizontal velocity and lower initial vertical velocity. This means the ball was in the air for less time. the 35° angle had a higher initial vertical and lower horizontal velocity, but was in the air for longer. This extra hang time means that the ball was able to travel farther before hitting the ground. 
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3 years ago
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Scott travels north 3 Km and then goes west 3 Km before coming straight
den301095 [7]

Answer:

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3km,W

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Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is a. The sound intensity i
leonid [27]

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are \dfrac{\lambda}{2}

Thus; for both speakers; the wavelength of the sound is:

\dfrac{\lambda}{2} = (10+30) cm

\dfrac{\lambda}{2} = (40) cm

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

\pi \ rad  = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o

\pi \ rad  = \dfrac{2 \pi}{8}+ \Delta \phi_o

\pi \ rad  = \dfrac{ \pi}{4}+ \Delta \phi_o

\Delta \phi_o  =  \pi -\dfrac{ \pi}{4}

\Delta \phi_o  = \dfrac{ 4\pi - \pi}{4}

\Delta \phi_o  = \dfrac{ 3\pi}{4} \ rad

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad

\Delta \phi = \dfrac{3 \pi}{4} \ rad

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)

A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)

A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)

A = 0.765a

7 0
3 years ago
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