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3 years ago

6

A hotel chain wants to estimate the mean number of rooms rented daily in a given month. The population of rooms rented daily is

assumed to be normally distributed for each month with a standard deviation of 240 rooms. During February, a sample of 25 days has a sample mean of 370 rooms. True or False: A 90% confidence interval calculated from the same data would be narrower than a 99% confidence interval.

1 answer:

Mekhanik [1.2K]3 years ago

8 0

The problem is TRUE because as listed, "During February, a sample of 25 days has a sample mean of 370 rooms" that gives you the answer.

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How many sites are show in this data set?

andre [41]

Answer:

The total number of sites are 15 .

Step-by-step explanation:

As shown in question.

The number of sites in 2 shield darter = 3

The number of sites in 3 shield darter = 1

The number of sites in 4 shield darter = 4

The number of sites in 6 shield darter = 2

The number of sites in 7 shield darter = 3

The number of sites in 8 shield darter = 1

The number of sites in 9 shield darter = 1

Thus

Total number of sites = Number of sites in 2 shield darter + Number of sites in 3 shield darter + Number of sites in 4 shield darter + Number of sites in 6 shield darter + Number of sites in 7 shield darter + Number of sites in 8 shield darter + Number of sites in 9 shield darter

Putting the values in above

= 3 + 1 + 4 + 2 + 3 + 1 +1

= 15

Therefore the total number of sites are 15 .

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2 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

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3 years ago

1. Identify the pair of fractions equivalent to 25/45 *

stepladder [879]

Answer:

Hope this helps! Brainliest please

Step-by-step explanation:

1. Divide both by 5, so the correct answer would be 5/9, and then multiply both by 3, so the correct answer would be 75/135. The answer is 5/9,75/135

2. 4 and 2/7 because 7 *4=28. That leaves 2 sevenths over.

3. Divide both by 9. Your answer is 3/4

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3 years ago

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anastassius [24]

Answer:

(f o h)(x) = -10x + 32

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Composite Functions

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x³ + 8

h(x) = ∛(12 - 5x)

(f o h)(x) is f(h(x))

<u>Step 2: Find Composite Function</u>

Substitute: (f o h)(x) = 2(∛(12 - 5x))³ + 8
Evaluate: (f o h)(x) = 2(12 - 5x) + 8
Distribute 2: (f o h)(x) = 24 - 10x + 8
Combine like terms: (f o h)(x) = -10x + 32

And we have our final answer!

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2 years ago

X + 3 =8<br> X- 5 =7 <br> Please someone help?

Sav [38]

Step-by-step explanation:

x+3=8

8-5=3 so x=5

7+5=12 / 12-7=5

12-5=7

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2 years ago

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