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Vika [28.1K]
3 years ago
8

9-3÷ 1/3 + 1= plz answer correctly because i can get grounded and I will give brainliest and give 20 points

Mathematics
2 answers:
fgiga [73]3 years ago
6 0
The answer should be 1
Bumek [7]3 years ago
3 0
The answer is 19.0000002
explanation: 9-3 is 6
turn 1/3 into a decimal
6 divided by 1/3 is 18.0000002
18.0000002 + 1 is 19.0000002
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Sam invests $9,400 in a fund yielding 5.2% simple interest annually. At the same time, Pat shops around for a better interest ra
Goryan [66]
Pat's fund earned is $526.40 more than Sam's fund.

Sam's investment :
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Pat's investment :
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$3,948.00-$3,421.60=$562.40

The answer to your question is going to be D. $526.40.

Hope this helps you!!:))
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2 years ago
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In the figure below, Line k is perpendicular to Line l. Based on the information given in the figure, find the measure of ∠B
Serggg [28]

Answer:

120

Step-by-step explanation:

5 0
2 years ago
Will give brainiest to whoever figured this out
meriva

Answer:

your answer will be <u>0.0001042</u>

Step-by-step explanation:

hope it helps

have a wonderful day

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2 years ago
Miss Jones gets 4 membership points for every £25 she spends in a shop.
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2 years ago
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50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST
Inessa [10]

Answer:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

Step-by-step explanation:

We are given the function:

f(x)=3+|2x-5|

Remember that by the definition of absolute value:

\displaystyle |x|= \left\{        \begin{array}{ll}            x & \quad x \geq 0 \\        -    x & \quad x < 0        \end{array}    \right.

Our absolute value is:

|2x-5|

First, we will find when it becomes 0. Set the equation equal to 0:

2x-5=0

Solve for <em>x: </em>

<em />x=5/2<em />

<em />

So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.

For all values less than <em>x </em>= 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

|2x-5|= \left\{        \begin{array}{ll}            2x-5 & \quad x \geq 5/2 \\           -(2x-5) & \quad x < 5/2         \end{array}    \right.

Finally, we can add a three:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            3+(2x-5) & \quad x \geq 5/2 \\            3+(-(2x-5)) & \quad x < 5/2        \end{array}    \right.

Simplify if desired:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

5 0
2 years ago
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