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nata0808 [166]
3 years ago
13

What is the perimeter This Pythagorean theorem

Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer:

a is 5 so the perinmeter is 30

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Kiera's dance class starts at 4:30pm and ends at 6:15 pm how long is her dance class <br><br>​
svp [43]
Kiera's dance class is 1 hour and 45 minutes long (1:45)
8 0
3 years ago
Melinda has a goal of donating at least $300 to charity this year. Her mother and father each gave her $25 to help and she is se
yulyashka [42]

Answer:

50

Step-by-step explanation:

25x2=50

300-50=250

250/5=50

50 ribbons needed :) hope this helped

8 0
1 year ago
Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 o
dimulka [17.4K]

Answer:

The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.

Step-by-step explanation:

The amount of water in the tank after 15 days is given by the series

910+(−710)+810+(−610)+⋯+310+(−110)+210

From the series, we can observe that, if water is added for a particular day then water will be drained the following day.

Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.

Hence, we can complete the series thus:

910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210

To evaluate this, we  get

910-710+810-610+710-510+610-410+510-310+410-210+310-110+210

= 1610.0 gallons

Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.

8 0
3 years ago
Two trains leave New York at the same time heading in opposite directions. Train A travels at 4/5 the speed of train one. After
grandymaker [24]
<h3>Answer:  </h3><h3>speed of train A = 44 mph</h3>

=============================================

Work Shown:

x = speed of train A

y = speed of train B

"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y

distance = rate*time

d = x*7

d = (4/5)y*7 = (28/5)y represents the distance train A travels

d = y*7 = 7y represents the distance train B travels

summing those distances will give us 693

(28/5)y + 7y = 693

5*(  (28/5)y + 7y ) = 5*693

28y + 35y = 3465

63y = 3465

y = 3465/63

y = 55

Train B's speed is 55 mph

4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph

Train A's speed is 44 mph

8 0
3 years ago
At a self-service gas station, 40% of customers pump regular gas, 35% pump midgrade, and 25% pump premium gas. Of those who pump
Aleks04 [339]

Answer:

0.150,0.595

Step-by-step explanation:

Given that at a self-service gas station, 40% of customers pump regular gas, 35% pump midgrade, and 25% pump premium gas. Of those who pump regular, 30% pay at least $30. Of those who pump midgrade, 50% pay at least $30. And of those who pump premium, 60% pay at least $30.

               Regular gas          Midgrade         Premium gas      Total

Percent      40                            35                     25                   100

atleast 30   30%                         50%                 60%

a) The   probability that the next customer pumps premium gas and pays at least $30

=0.25*0.60\\=0.150

b)        the probability that the next customer pays at least $30

= P(regular and pays atleast 30%)+P(premium and pays atleast 30%)+P(midgrade and       pays atleast 30%)

=0.40*0.30+0.35*0.50+0.25*0.60\\=0.12+0.175+0.30\\=0.595                  

6 0
3 years ago
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