<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%7Bx%20%7B5%7D%5E" id="TexFormula1" title="y = \sqrt{x {5}^" alt="y = \s

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vampirchik [111]

2 years ago

qrt{x {5}^" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Sedaia [141]2 years ago

6 0

Y=y to the third and multiple

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Hello please help posted picture of question

Lynna [10]

Answer:

A. True

Step-by-step explanation:

All function of the form y = a^x, where a is a positive constant, goes through the point (0,1) and y = 0 is the asymptote.

Also note, a function y = a^x + k is a vertically translated function from the parent (y=a^x) k units up.

So, the function F(x) = 7 + 3^x is basically 3^x translated 7 units. What happens is that the point (0,1) gets translated 7 units above, so this point becomes (0,1+7)=(0,8). and the asymptote is y = 7.

Hence the function starts from above y = 7 (y = 7 is asymptote), goes through (0,8) and increases. Hence the Range would be all numbers GREATER than 7 (till infinity).

So, the question is TRUE.

4 0

3 years ago

bob has 20 apples, billy has 20 pears, bob gives 4 pears to his little sister, billys uncle gives him 69 bananas. What is the di

AysviL [449]

Answer:

Step-by-step explanation:

Bob

20-4=16

Billy 20+69=89

89-16=73

5 0

2 years ago

The proprietor of a boutique in New York wanted to determine the average age of his customers. A random sample of 25 customers r

jolli1 [7]

Answer:

$28-2.064\frac{10}{\sqrt{25}}=23.872$

$28+2.064\frac{10}{\sqrt{25}}=32.128$

So on this case the 95% confidence interval would be given by (23.9;32.1)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=28$ represent the sample mean

$\mu$ population mean (variable of interest)

s=10 represent the sample standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that $t_{\alpha/2}=2.064$