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2 years ago

What is the x-intercept of the function graphed below?

Mathematics

1 answer:

erastovalidia [21]2 years ago

6 0

Answer:

2....

Step-by-step explanation:

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A large company put out an advertisement in a magazine for a job

vova2212 [387]

Answer:

<em>C(19)=12 responses</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is frequently used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function can be expressed as follows:

$C(t)=C_o\cdot(1-r)^t$

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The company puts out an advertisement for a job opening. Initially, the company got 90 responses to the advertisement. Each day, the responses declined by 10%.

This is an example where the decay model can be used to calculate the responses to the advertisement at the day t.

The initial value is Co=90, the decaying rate is r=10% = 0.10. The model is written as:

$C(t)=90\cdot(1-0.1)^t$

Calculating:

$C(t)=90\cdot(0.9)^t$

We are required to calculate the number of responses at day t=19, thus:

$C(19)=90\cdot(0.9)^{19}$

C(19)=12 responses

8 0

2 years ago

The table below shows the amount of time a light stays green, red, and yellow (for one cycle) during the day and during the nigh

Lady_Fox [76]

Answer:i am sorry bud i have nio ideavjkfdav

Step-by-step explanation:fdanmfva e.dn f,da/

6 0

2 years ago

During the 2010 Great Backyard Bird Count, an average of

Phantasy [73]

Answer:

good luck

Step-by-step explanation:

7 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :