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Mrrafil [7]
2 years ago
5

A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into th

e trailer is 1,050 pounds. An 82-pound crate has already been loaded onto the trailer. What is the greatest number of 40-pound crates that can be loaded onto the trailer?
Mathematics
1 answer:
docker41 [41]2 years ago
7 0

Given :

A trailer will be used to transport several 40-pound crates to a store.

The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.

An 82-pound crate has already been loaded onto the trailer.

To Find :

The greatest number of 40-pound crates that can be loaded onto the trailer.

Solution :

Weight left = 1050 - 80 = 970 pound.

Let, number of 40 pounds crates that can be loaded are x.

x  = \dfrac{970}{40}\\\\x = 24.25

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.

Hence, this is the required solution.

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Answer:

Equation is  A = 5000(1.015)^(4t)

Her investment will be worth $10,000 in about <u>11.63888 years</u>

Rounding up to the nearest whole number gets to <u>12 years</u>

==========================================================

Explanation:

Part 1) Finding the equation

The compound interest formula is

A = P(1+r/n)^(n*t)

Here are the variables

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  • P = starting amount, or deposit, or principal
  • r = interest rate in decimal form
  • n = number of times money is compounded per year
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Therefore, the equation is

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--------------------------

Part 2) Let's plug in A = 10,000 and solve for t.

You'll need to use logarithms to isolate the exponent.

A = 5000(1.015)^(4t)

10,000 = 5000(1.015)^(4t)

10,000/5000 = (1.015)^(4t)

2 = (1.015)^(4t)

Log[ 2 ] = Log[ (1.015)^(4t) ]

Log(2) = 4t*Log( 1.015 )

4t = Log(2)/Log(1.015)

4t = 46.5555256308062

t = 46.5555256308062/4

t = 11.6388814077015

t = 11.63888

It takes about 11.63888 years for the investment to reach $10,000.

Therefore, at the 12 year mark is when the investment is more than $10,000.

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