A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into th
1 answer:
Given :
A trailer will be used to transport several 40-pound crates to a store.
The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.
An 82-pound crate has already been loaded onto the trailer.
To Find :
The greatest number of 40-pound crates that can be loaded onto the trailer.
Solution :
Weight left = 1050 - 80 = 970 pound.
Let, number of 40 pounds crates that can be loaded are x.
Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.
Hence, this is the required solution.
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Answer:
Bruce's line is steeper and his line is also greater,yes
Step-by-step explanation:
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Answer:
a) 15.87% of the scores are expected to be greater than 600.
b) 2.28% of the scores are expected to be greater than 700.
c) 30.85% of the scores are expected to be less than 450.
d) 53.28% of the scores are expected to be between 450 and 600.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a. Greater than 600
This is 1 subtracted by the pvalue of Z when X = 600. So
has a pvalue of 0.8413.
1 - 0.8413 = 0.1587
15.87% of the scores are expected to be greater than 600.
b. Greater than 700
This is 1 subtracted by the pvalue of Z when X = 700. So
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% of the scores are expected to be greater than 700.
c. Less than 450
Pvalue of Z when X = 450. So
has a pvalue of 0.3085.
30.85% of the scores are expected to be less than 450.
d. Between 450 and 600
pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So
X = 600
has a pvalue of 0.8413.
X = 450
has a pvalue of 0.3085.
0.8413 - 0.3085 = 0.5328
53.28% of the scores are expected to be between 450 and 600.
Answer:
Area of tissue paper is 384 square inches.
Step-by-step explanation:
Given:
Length of box = 16 inches.
Width of the box = 12 inches.
We need to find find the area of the tissue paper.
But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.
Hence Framing in equation form we get;
Area of tissue paper =
Hence Substituting the given values we get;
Area of tissue paper =
Hence Area of tissue paper is 384 square inches.