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Mrrafil [7]
2 years ago
5

A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into th

e trailer is 1,050 pounds. An 82-pound crate has already been loaded onto the trailer. What is the greatest number of 40-pound crates that can be loaded onto the trailer?
Mathematics
1 answer:
docker41 [41]2 years ago
7 0

Given :

A trailer will be used to transport several 40-pound crates to a store.

The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.

An 82-pound crate has already been loaded onto the trailer.

To Find :

The greatest number of 40-pound crates that can be loaded onto the trailer.

Solution :

Weight left = 1050 - 80 = 970 pound.

Let, number of 40 pounds crates that can be loaded are x.

x  = \dfrac{970}{40}\\\\x = 24.25

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.

Hence, this is the required solution.

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What is absolute value
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Absolute value is the distance between a point and 0. Absolute value is always positive. When you're writing numbers in absolute value, make sure you add:

| |

The absolute value of a negative number is also positive. For example:

| -7 | = 7 ⇒The absolute value of -7 is 7.

3 0
3 years ago
Please someone solve for X, I don’t think it needs rounding but I couldn’t come up with an answer.
agasfer [191]

Answer:

x= 10 In (17)

Step-by-step explanation:

5 0
3 years ago
Please help me !!!!!!!
NikAS [45]
I want to say the answer is A i caulated it and i end up getting 17
4 0
2 years ago
A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula
kvasek [131]

Answer:

The sample proportion of printers used in small business is:

\hat{p}=\frac{25}{70}=0.3571

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

Where:

z_{\frac{0.05}{2}}=1.96 is the critical value at 0.05 significance level

\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }

         0.3571 \pm 0.1122

         \left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)

         \left(0.245,0.469 \right)

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)



7 0
3 years ago
What is the best approximation for the area of a circle diameter of 19 m?
Maslowich
The formula for an area of a circle is 
A=pi times radius squared

there for you do pi times 9.5 to the power of two/squared (radius is half of the diameter so 19 divided by 2 is 9.5) 

pi times 9.5 squared 
= 283.5

I rounded to the nearest tenths


7 0
3 years ago
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