You need the formula for geometric mean for right triangles as it applies to the altitude. For us, that formula will be where BD is your altitude. The formula then, filled in accordingly, would be
. We cross multiply to get that
. Divide both sides by 4 to get
, so x = 5. Choice C is the one you want.
A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t
Solve for t
Solve using quadratic formula
After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
A and E
Step-by-step explanation:
Given
20x² - 26x + 8 = 0 ( divide through by 2 )
10x² - 13x + 4 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 10 × 4 = 40 and sum = - 13
The factors are - 5 and - 8
Use these factors to split the x- term
10x² - 5x - 8x + 4 = 0 ( factor the first/second and third/fourth terms )
5x(2x - 1) - 4(2x - 1) = 0 ← factor out (2x - 1) from each term
(2x - 1)(5x - 4) = 0
Equate each factor to zero and solve for x
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = → E
5x - 4 = 0 ⇒ 5x = 4 ⇒ x = → A