The area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
<h3> Area of Peter's soccer net</h3>
The area of Peter's soccer net is determined by using area of rectangle as shown below;
A1 = 5.5 ft x 4 ft
A1 = 22 ft²
<h3> Area of Jill's soccer net</h3>
A2 = 5.5 ft x 12 ft
A2 = 66 ft²
<h3>Ratio of the area of their soccer net</h3>
A2/A1 = 66/22
A2/A1 = 3
Thus, the area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
Learn more about area of rectangle here: brainly.com/question/25292087
Answer:
HCF Of two nos. is 17
Let another no. be x
we know that HCF ×LCM = Product of two numbers
17×140=20×(x)
20x=2380
x =2380/20
x=119
The other no. is 119
Answer:
..
Step-by-step explanation:
Answer:
The formula to find the volume of a cube : s^3 so
S=40 cm
Now
by the formula,
40^3
64000
Answer:
a. Yes. p-value(0.05469)> 0.05
b,c- see details below
Step-by-step explanation:
a. #Use shapiro test to test for normality
Yes. The population has a p-value greater than 0.05:
0.05469>0.05
b.From our output, the 98% intervals are:
[8.19016,9.648021]
c. The new interval, [8.19016,9.648021] is wider, but we are more confident that it contains the true mean ( 8.919091)
#Attached histogram and snippet of the applicable code.