Yes JKLM would be a parallelogram.
We are given traingle ABC and Triangle DEF.
Angle <A is congruent to Angle <D
Angle <B is congruent to Angle <E
Angle <C is congruent to Angle <F.
If two pairs of corresponding angles are congruent to each other, then the triangles are similar by Angle-Angle Similarity.
<em>By Angle-Angle similarity postulate triangle ABC and triangle DEF are similar.</em>
Therefore, option C is correct option.
<h3>
C. Similar - AA.</h3>
Answer:
<u>202</u><u>5</u>
Step-by-step explanation:
3n² is our nth term
n=15
thus....
(3×15)²
= 45²=<u>202</u><u>5</u>
Hopefully this helped- have a great day)
Answer:
A= -u²n²t²s²arme²
Step-by-step explanation:
Evaluate m, then set it equal to 15.
=15
Evaluate s, the set it equal to 2.
=2
Simplify unitsareminutes.
−u²n²t²s²arme²
List all the solutions.
BN•N=BN²
m=15 ==15
s=2 2==2
The slope of line D is also -4 because the lines are perpendicular.
