If Jk=5x+1 and KL=7x-3 K is the midpoint of JL what is JL
1 answer:
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Answer:
Step-by-step explanation:
(27)^2/3=∛27²=∛3³*3³=3*3=9
√36³=√36*36*36=√6²*6²*6²=6*6*6=216
(-243)^3/5=5√2-42³=-27
Answer:
Step-by-step explanation:
(27)^2/3=∛27²=∛3³*3³=3*3=9
√36³=√36*36*36=√6²*6²*6²=6*6*6=216
(-243)^3/5=5√2-42³=-27