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Zarrin [17]
3 years ago
10

Stevens bank account balance was $212 at the beginning of the month he withdrew $63,$74 and $39 he also deposited $105 and $86 w

hat was his balance after these transactions
Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

$227

Step-by-step explanation:

First we can add up the withdrawals(63, 74, and 39) which is 176. We can then subtract 176 from 212 to get 36.

So, after the withdrawals Steven has 36 dollars.

We can add the deposits together to get 191. We can then add 191 to 36 to get 227.

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3x+7=13 (x=-2;x=2;x=5)
AnnZ [28]
X=2 because 3 times 2 is 6 and then you add 6 and 7 together and get 13.
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A regular hexagon has a radius of 20 in. What is the approximate area of the hexagon?
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1,038 in2

Step-by-step explanation:

In a regular hexagon, the radius and side length are equal in length... That makes the answer 1038 in.2 correct?

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What’s the equation.
cestrela7 [59]

Answer:

c=42

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Step-by-step explanation:

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3 years ago
Can you explain how to do 13 please
Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
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3 years ago
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Mrac [35]
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We go to the tenth's place, which is 9. Since 9 is higher than 5, we need to round the hundredth's place to 3.
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