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Sidana [21]
2 years ago
12

Solve (x + 9)^2 = 25.

Mathematics
2 answers:
m_a_m_a [10]2 years ago
7 0

Answer:

if x + 9 = 5 then x = -4

if x + 9 + -5 then x = -14

Step-by-step explanation:

I dont know how to explain it.  

But it was right on ingenuity

Katena32 [7]2 years ago
6 0

if x + 9 = 5 then x = -4

if x + 9 + -5 then x = -14

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Does the frequency distribution appear to have a normal​ distribution? Explain. Temperature ​(degrees​F) Frequency 35 dash 39 1
AlexFokin [52]

Answer:

D. ​Yes, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is approximately symmetric.

Step-by-step explanation:

Hello!

The given frequency distribution for temperatures.

To see if the distribution appears to have a normal distribution you have to draw a histogram using the information. Check attachment.

As you can see, the distribution appears symmetric, it starts low and proceeds to grow until it reaches its maximum point (f(4)=13) and then starts to decrease to low frequencies. The right tail decreases a little more than the left one but it is almost symmetrical.

I hope this helps!

5 0
3 years ago
Find the y-intercept of the line on the graph
Kitty [74]
The Y-intercept is -4 because it's located on the y-axis you can remember that the y-axis is up and down the x-axis is side to side.
7 0
2 years ago
Find equations of the spheres with center(3, −4, 5) that touch the following planes.a. xy-plane b. yz- plane c. xz-plane
postnew [5]

Answer:

(a) (x - 3)² + (y + 4)² + (z - 5)² = 25

(b) (x - 3)² + (y + 4)² + (z - 5)² = 9

(c) (x - 3)² + (y + 4)² + (z - 5)² = 16

Step-by-step explanation:

The equation of a sphere is given by:

(x - x₀)² + (y - y₀)² + (z - z₀)² = r²            ---------------(i)

Where;

(x₀, y₀, z₀) is the center of the sphere

r is the radius of the sphere

Given:

Sphere centered at (3, -4, 5)

=> (x₀, y₀, z₀) = (3, -4, 5)

(a) To get the equation of the sphere when it touches the xy-plane, we do the following:

i.  Since the sphere touches the xy-plane, it means the z-component of its centre is 0.

Therefore, we have the sphere now centered at (3, -4, 0).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, -4, 0) as follows;

d = \sqrt{(3-3)^2+ (-4 - (-4))^2 + (0-5)^2}

d = \sqrt{(3-3)^2+ (-4 + 4)^2 + (0-5)^2}

d = \sqrt{(0)^2+ (0)^2 + (-5)^2}

d = \sqrt{(25)}

d = 5

This distance is the radius of the sphere at that point. i.e r = 5

Now substitute this value r = 5 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 5²  

(x - 3)² + (y + 4)² + (z - 5)² = 25  

Therefore, the equation of the sphere when it touches the xy plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 25  

(b) To get the equation of the sphere when it touches the yz-plane, we do the following:

i.  Since the sphere touches the yz-plane, it means the x-component of its centre is 0.

Therefore, we have the sphere now centered at (0, -4, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (0, -4, 5) as follows;

d = \sqrt{(0-3)^2+ (-4 - (-4))^2 + (5-5)^2}

d = \sqrt{(-3)^2+ (-4 + 4)^2 + (5-5)^2}

d = \sqrt{(-3)^2 + (0)^2+ (0)^2}

d = \sqrt{(9)}

d = 3

This distance is the radius of the sphere at that point. i.e r = 3

Now substitute this value r = 3 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 3²  

(x - 3)² + (y + 4)² + (z - 5)² = 9  

Therefore, the equation of the sphere when it touches the yz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 9  

(b) To get the equation of the sphere when it touches the xz-plane, we do the following:

i.  Since the sphere touches the xz-plane, it means the y-component of its centre is 0.

Therefore, we have the sphere now centered at (3, 0, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, 0, 5) as follows;

d = \sqrt{(3-3)^2+ (0 - (-4))^2 + (5-5)^2}

d = \sqrt{(3-3)^2+ (0+4)^2 + (5-5)^2}

d = \sqrt{(0)^2 + (4)^2+ (0)^2}

d = \sqrt{(16)}

d = 4

This distance is the radius of the sphere at that point. i.e r = 4

Now substitute this value r = 4 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 4²  

(x - 3)² + (y + 4)² + (z - 5)² = 16  

Therefore, the equation of the sphere when it touches the xz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 16

 

3 0
3 years ago
Convert 68°C to degrees Fahrenheit. If necessary, round your answer to the nearest tenth of a degree
Karolina [17]

Answer: 154.4 Fahrenheit

Step-by-step explanation: 68°C = ( 68× 9 / 5 + 32 ) = 154.4°F

6 0
3 years ago
The value of a $3000 computer decreases about 30% each year. write a function for the computers value V(t)
den301095 [7]

Answer:

Function for given situation is : V(t)=3000(0.70)^t

Value of computer after 4 years = $720.3.

Step-by-step explanation:

Given that the value of a $3000 computer decreases about 30% each year. Now we need to write a function for the computers value V(t). then we need to find about how much will the computer be worth in 4 years.

It clearly says that value decreases so that means function represents decay.

For decay we use formula:

A=P(1-r)^t

where P=initial value = $3000,

r= rate of decrease =30% = 0.30

t= number of years

A=V(t) = future value

so the required function is V(t)=3000(1-0.30)^t

or V(t)=3000(0.70)^t

Now plug t=4 years to get the value of computer after 4 years.

V(4)=3000(0.70)^4

V(4)=720.3

Hence final answer is $720.3.

7 0
2 years ago
Read 2 more answers
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