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2 years ago

5

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

2 answers:

vazorg [7]2 years ago

6 0

You are gonna use a^2 + b^2 = c^2 because the cities make a right triangle and you are trying to find the hypotenuse (c). C^2 ends up being 517 and the square root, your answer, is 22.7 miles

SSSSS [86.1K]2 years ago

5 0

Answer:

$22.67 miles\\$

Step-by-step explanation:

Suppose the position of Abbotsford is at the center of the graph, then Hawick lies to its south at 90 degrees and Kelso lies to its east at 90 degrees

So both Hawick and Kelso becomes the two end points of the hypotenuse

So the length of hypotenuse $= \sqrt{15^2 + 17^2} \\= \sqrt{225 + 289} \\= \sqrt{514} \\\\= 22.67 miles\\$

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Serga [27]

Answer:

11 sq.ft

Step-by-step explanation:

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= 1/2 × 16 × ∅

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=8×(4π/9)

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2 years ago

Please Help I don’t get it at all N/2+5=3

eduard

N/2+5=3

move +5 to the other side

sign changes from +5 to -5

N/2+5-5= 3-5

N/2= -2

Mutiply both sides by 2/1

N/2*2/1 - Cross out 2 and 2 , divide by 2 then becomes N

-2(2)/1= -4/1= -4

N= -4

Answer : N= -4

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2 years ago

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The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

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2 years ago

The gardener is going to cover the path with sand. If one bag of sand can cover 5yd^2, how many bags must be a whole number.

Nesterboy [21]

5 a bag of bags be can cover2 garden

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3 years ago

Write the equation of the parabola in vertex form.vertex (0,2), point (1,-5)

charle [14.2K]

Y=a(x-h)^2+k
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y=-3x^2+2

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3 years ago

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