Answer:
so you would replace all r with 2 which is 2+q-2
then replace the q with 6 so it would be: r+6-r
combined both of these to get
2+6-2
which would equal to 6
add the 2 and the 6 to get 8
then subtract 2 to get 6
Yes if he practices X amount of hours and is told to practice X amount of hours than he practiced long enough
24% .61 2/3 two thirds is .66 24% is .24 and .61 is .61
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
55% of the people surveyed were satisfied with the car
Step-by-step explanation:
The proportion of people surveyed who were satisfied with the car is the number of people who said they would buy that type of car again divided by the total number of people survied.
The percentage is the proportion multiplied by 100.
We have that:
2,300 people surveyed
1,265 said they would buy that type of car again.
1265/2300 = 0.55
0.55*100 = 55%
55% of the people surveyed were satisfied with the car
