Answer:
32.5 units²
Step-by-step explanation:
We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.
First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.
5 · 5 = 25 units²
Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.
8 - 5 = 3
So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.
5 · 3 = 15
= 7.5
The area of the triangle is 7.5 units².
Finally, we can add the area of the triangle and the square together.
25 + 7.5 = 32.5
The area of the figure, then, is 32.5 units².
The answer is the last option.
I hope this helps ^^
Answer:
jnjnmmknkn
Step-by-step explanation:
X² - 5 + -24
x² - 5 - 24
x² + (-5 - 24)
x² + 29
hope this helps, God bless!
The same step is to place the compass on the endpoint of the segment. So, the correct option is C.
Given the statement is copying a segment and bisecting a segment.
A segment is a set of points made up of two points on the line, called endpoints, and all points on the line between the endpoints. It is commonly used to represent the length, height or width of a specific object and the distance between two objects.
According to the geometry theorem, When copying a segment and bisecting a segment the step that is the same is placing the needle of the compass on one end of the line segment.
Hence, When copying a segment and bisecting a segment the same step is to place the compass on the endpoint of the segment.
Learn more about segment and bisection from here brainly.com/question/1581615
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Answer: the velocity and position vector is given by;
v(t) = 3i + 2j + (1-32t)k
r(t) = (3t)i + (5-2t)j + (2+t-16t^2)k
The position at time t=2; r(2)
r(2) = 6i + j - 60k
Step-by-step explanation:
Shown in the attachment.
