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VLD [36.1K]
2 years ago
10

Please help me need ASAP

Mathematics
1 answer:
Ket [755]2 years ago
4 0

Answer:

preety sure its answer 3

Step-by-step explanation:

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Is 3.1245769 a irrational number or a rational
tensa zangetsu [6.8K]
Rational im pretty sure from what i remember
8 0
3 years ago
-5/4-(-1/6) help please
tiny-mole [99]
A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.
\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{d}+\dfrac{c}{d}\cdot\dfrac{b}{b}\\\\=\dfrac{ad+bc}{bd}

Here, you have
\dfrac{-5}{4}-\dfrac{-1}{6}=\dfrac{-5\cdot6-(-1)\cdot4}{4\cdot6}=\dfrac{-26}{24}\\\\=\dfrac{-13}{12}=-1\frac{1}{12}

The sum is -1 1/12
3 0
3 years ago
Find the value of x then classify the triangle by its angles
Neporo4naja [7]

Answer:

Step-by-step explanation:

3x + x + 60 = 180.

first, we add the x's together.

4x + 60 = 180

then we see if they all have a common multiple. in this case, they do. they are all divisible by 4, so we can use that.

x + 15 = 45

then, just subtract 15 from both sides, that way we get the variable by itself.

x = 30

also, it is a right triangle. the top angle (3x) multiplied by 3 is 90. any triangle that has a 90 degree angle is automatically a right triangle.

6 0
2 years ago
Read 2 more answers
Todos los numeros naturales son enteros​
Mamont248 [21]
Pee brain. . .you get it okay
7 0
2 years ago
Read 2 more answers
Help Fast Please!!!!!!!!! How can you tell if three positive numbers form a Pythagorean triple?
Fiesta28 [93]

Answer/Step-by-step explanation:

Square all three numbers. If the largest number squared is equal to the sum of the squares of the other two, then the numbers form a Pythagorean triple.

<u><em>or</em></u>

Since a Pythagorean triple is three positive integers a, b, and c such that (a^2)+(b^2)=(c^2), first take the sum of the squares of the two legs and make an estimate. For example, 3, 4, and 5 is a Pythagorean triple since 9+16=25

<u><em>either one works</em></u>

3 0
3 years ago
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