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rodikova [14]
2 years ago
10

Consider these dimensions for a cylindrical aquarium.

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0

The amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

<h3>What is a Cylindrical figure ?</h3>

A cylinder is a three dimensional figure with two identical circular faces at each end , and a curved surface.

It does not have an edges or vertices.

It is given in the question that

A cylinder with height 14 feet and radius 25 feet.

The volume of a cylinder.

V = π252(14)

The water than can be filled is equal to the volume of the cylinder

V = 11088 cu.ft

There  the amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

To know more about Cylindrical Figure

brainly.com/question/10369419

#SPJ1

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HELLPPPPP PLEASEEE HURRY FIND THE SURFACE AREA OF THE PYRAMID
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In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294
slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

a_4=54 and a_7=1458

To find a_{12}:

The given sequence is a geometric sequence.

The general term of the geometric sequence is a_n=a_1\ r^{n-1}.

If we have 2 terms of a geometric sequence a_n and a_k (n > K),

then we can write the general term as a_n=a_k\ r^{n-k}.

Here we have a_4=54 and a_7=1458.

So, n = 7 and k = 4 ( 7 > 4)

a_7=a_4\ .\ r^{7-4}

1458=54\ . \  r^3

This can be written as

$r^3=\frac{1458}{54}

$r^3=27

$r^3=3^3

Taking cube root on both sides of the equation, we get

r = 3

a_{12}=a_7\ .\ r^{12-7}

     =1458\ .\ r^5

     =1458\ .\ 3^5

a_{12}=354294

Hence the 12th term of the geometric sequence is 354294.

7 0
3 years ago
1/3 divided by 3/4 = simplified
GenaCL600 [577]

Answer:

4/9

Step-by-step explanation:

1/3 divided by 3/4

find the reciprocal of 3/4

reciprocal of 3/4 = 4/3

multiply 1/3 x 4/3 which is 4/9

4 0
2 years ago
PLEASE HELP!!! <br> BRAINLYEST!!!
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Answer:

C

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

Note that 8 = 2³, thus

\frac{2^{5} }{8}

= \frac{2^{5} }{2^{3} }

= 2^{(5-3)}

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