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2 years ago

Consider these dimensions for a cylindrical aquarium.

Mathematics

1 answer:

vagabundo [1.1K]2 years ago

6 0

The amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

<h3>What is a Cylindrical figure ?</h3>

A cylinder is a three dimensional figure with two identical circular faces at each end , and a curved surface.

It does not have an edges or vertices.

It is given in the question that

A cylinder with height 14 feet and radius 25 feet.

The volume of a cylinder.

V = π252(14)

The water than can be filled is equal to the volume of the cylinder

V = 11088 cu.ft

There the amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

To know more about Cylindrical Figure

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I'm super confused on parts g and h because no formula is given, just the limit values. These are the values:

Mrrafil [7]

Answer:

See below.

Step-by-step explanation:

So we have the limit:

$\lim_{x\to 4} (f\circ g)(x)$

This is equivalent to:

$\lim_{x\to 4} f(g(x))$

To solve, we can use the following property:

$\lim_{x \to c} f(g(x))=f( \lim_{x \to c} g(x))$

Therefore, our limit is the same as:

$\lim_{x\to 4} f(g(x))\\=f(\lim_{x\to 4} g(x))$

We are already given that the limit as x approaches 4 of g(x) is -2. Therefore:

$=f(-2)$

You simply need to evaluate this to solve the limit. I don't have enough information to solve this, so maybe you have something more.

Similarly, for the second one:

We have:

$\lim_{x\to 4} (g\circ f)(x)\\=\lim_{x\to 4}g(f(x))$

Using the same property:

$=g(\lim_{x\to 4} f(x))$

And we are told that this is 16, so:

$=g(16)$

And we just need to evaluate this to find the limit.

I hope you find this helpful!

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3 years ago

Todd begins piano practice ar 4:15 p.m. and ends at 5:50 p.m. How long does he practice

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4 years ago

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For thousands of years, gold has been considered one of the earth's most precious metals. one hundred percent pure gold is24-

Leona [35]

14 karat gold is 58.3333...% gold
We have 75% gold and 50% gold and we need to make 200 grams of 58.3333...% gold.

A) x + y = 200

B) .75x + .50y = ( (14/24) * 200)
We multiply equation B) by -1.3333... and get
B) -x -.6666...y = -155.5555... then adding A)
A) x + y = 200 we get

.3333...y = 44.4444...

y = 133.3333... grams 12 karat gold
x = 66.6666... grams 18 karat gold

Double-Checking the answer
133.3333... * .5 = 66.6666...
66.6666 * .75 = 50.0000...

Concentration of final solution = (66.6666... + 50) / 200 = 58.3333...% which is 14 karat gold

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Answer:

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Step-by-step explanation:

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