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irinina [24]
3 years ago
5

F(x)=-x^2+19 Find f(3)

Mathematics
2 answers:
Arturiano [62]3 years ago
8 0

Answer:

f(3) = 10

Step-by-step explanation:

f(x)=-x^2+19

Let x= 3

f(x)=- (3)^2+19

    = -9 + 19

    = 10

Georgia [21]3 years ago
8 0

Answer: f(3) = 10

f(x) = -x^2 + 19

Now, the value of x would be 3

f(x)= - (3) squared 2 plus 19

-9 + 19 = 10

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Find the selling price for the item flash drive: $12 markup:35%​
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Answer:

16.2

Step-by-step explanation:

12*1.35=16.2

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Two students have examined the scatter plot shown and have created a line of best fit for the data. Student A believes that the
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Answer:

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8 0
2 years ago
A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January
Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that p = 0.23

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084

P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735

P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439

P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

E(X) = np = 10*0.23 = 2.3

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33

The expected number is 2.3 and the standard deviation is 1.33.

5 0
3 years ago
Mrs. Jennings had a 5/7 gallon of paint. She gave 1/7 gallon each to some students. How many students received paint if Mrs. Jen
Mumz [18]
You divied so your answer is 5 hope it helps
7 0
3 years ago
Read 2 more answers
Which is another way to check the sum of 104 + 34 + 228 + 877?
weqwewe [10]

By adding 104+34 and then 228+877, Then adding both of the results and finally subtracting the answer by one of the factors.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Explanation:

Which will be...

104+34=138

228+877=1,105

Then add them...

138+1,105=1,243

Finally, subtract your answer by one of the factors...

1,243-1,105

Which will result as 138. Which is also one of the factors you added earlier, that's basically what your looking fro when checking and subtraction and/or addition problem.

5 0
3 years ago
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