Can someone solve this for me pls?
1 answer:
Answer:
I believe x = 9
Hope This Helps and is right! So sorry if it's not!
Please rate and give thanks!
You might be interested in
Answer:
yes
Step-by-step explanation:
Answer:
x = 1.
Step-by-step explanation:
![\frac{1}{3}(6x-3)-\frac{1}{4}(20x+8)=-6\\\\[Distribute the first fraction into the parenthesis.]\\((\frac{1}{3}*6x)-(\frac{1}{3}*3))-\frac{1}{4}(20x+8)=-6\\\\2x-1-\frac{1}{4}(20x+8)=-6\\\\[Distribute the second fraction into the parenthesis.]\\2x-1-((\frac{1}{4}*20x)+(\frac{1}{4}*8))=-6\\\\2x-1-5x-2=-6\\\\[Combine like terms.]\\-3x-3=-6\\\\[Add 3 to both sides.]\\-3x=-3\\\\[Divide both sides by -3.]\\x=1](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%286x-3%29-%5Cfrac%7B1%7D%7B4%7D%2820x%2B8%29%3D-6%5C%5C%5C%5C%5BDistribute%20the%20first%20fraction%20into%20the%20parenthesis.%5D%5C%5C%28%28%5Cfrac%7B1%7D%7B3%7D%2A6x%29-%28%5Cfrac%7B1%7D%7B3%7D%2A3%29%29-%5Cfrac%7B1%7D%7B4%7D%2820x%2B8%29%3D-6%5C%5C%5C%5C2x-1-%5Cfrac%7B1%7D%7B4%7D%2820x%2B8%29%3D-6%5C%5C%5C%5C%5BDistribute%20the%20second%20fraction%20into%20the%20parenthesis.%5D%5C%5C2x-1-%28%28%5Cfrac%7B1%7D%7B4%7D%2A20x%29%2B%28%5Cfrac%7B1%7D%7B4%7D%2A8%29%29%3D-6%5C%5C%5C%5C2x-1-5x-2%3D-6%5C%5C%5C%5C%5BCombine%20like%20terms.%5D%5C%5C-3x-3%3D-6%5C%5C%5C%5C%5BAdd%203%20to%20both%20sides.%5D%5C%5C-3x%3D-3%5C%5C%5C%5C%5BDivide%20both%20sides%20by%20-3.%5D%5C%5Cx%3D1)
Yes the diagnols of the parallelogram are perpendicular because the angles are perpendicular bisects of each other
Answer:
-39
Step-by-step explanation:
a=-6 b=5 c=-2
a3-b+4c2
(-6)3-(5)+4(-2)2
