How do I do this? I need to simplify the answers
2 answers:
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Answer:
480.61g S
Step-by-step explanation:
I'm not sure what you meant in the parenthesis though. If you want the answer sig-figged it would be 481 g S. My work is attached, hope it helps!
The inequality is used to solve how many hours of television Julia can still watch this week is
The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours
<h3><u>Solution:</u></h3>Given that Julia is allowed to watch no more than 5 hours of television a week
So far this week, she has watched 1.5 hours
To find: number of hours Julia can still watch this week
<em>Let "x" be the number of hours Julia can still watch television this week</em>
"no more than 5" means less than or equal to 5 ( ≤ 5 )
Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours
number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch
Thus the above inequality is used to solve how many hours of television Julia can still watch this week.
Solving the inequality,
Thus Julia still can watch Television for 3.5 hours
Answer:
0.0025 = 0.25% probability that both are defective
Step-by-step explanation:
For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
5 percent of these are defective.
This means that
If two items are randomly selected as they come off the production line, what is the probability that both are defective
This is P(X = 2) when n = 2. So
0.0025 = 0.25% probability that both are defective