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3 years ago

Please help me I always sleep late doing homework and I do not want to today begging ya. You don’t have to do 1,2,3

Mathematics

1 answer:

Anika [276]3 years ago

5 0

Answer: 5, 18, 20, 25, 27, 35, 38, 40, 48, 60, 90

Step-by-step explanation: Count lol

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For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.

Sati [7]

The formula $C(n, r)= \frac{n!}{r!(n-r)!}$ , where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.

The sample space S in our problem is as follows:

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

$C(12, 2)=\displaystyle{ \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66$

So there are in total, 5*66= 330 possible triples.

n(S)=330

The event E "selecting 2 freshmen and 1 junior" can occur in :

$C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40$ many ways.

so n(E)=40

P(E)=n(E)/n(S)=40/330=0.12

Answer: 0.12

4 0

4 years ago

10. Lin says that a solution to the equation 2x – 6 = 7x must also be a solution to the

nirvana33 [79]

Answer:

Both give - 6=5x

Step-by-step explanation:

First equation 2x-6=7x

When you solve it, it becomes :

2x-6=7x

Subtract 2x both sides

2x-2x-6=7x-2x=

-6=5x

2)5x-6=10

5x-5x-6=10x-5x

-6=5x

3 0

3 years ago

What is the value of y? 3y+10/4=y

k0ka [10]

The answer is y=2. Hope this helps!

8 0

3 years ago

Square, one side length 2& 11 mile:

hodyreva [135]

That would be the one and only 22

8 0

3 years ago

1500 families were surveyed and following data was recorded about their maids at homes.

nika2105 [10]

Explanation:-

Total number of families are surveyed = 1500

Total number of possible outcomes = 1500

Number of part time maids = 860

Number of favourable outcomes to part time maids = 860

Number of only full time maids = 370

Number of favourable outcomes to only full time maids = 370

Number of both type of maids = 250

Number of favourable outcomes to both type of maids = 250

From all families selecting a family randomly is an event then

We know that

Probability of an event =

Number of favourable outcomes/Total number of possible outcomes

1⟩ Probability of getting both type of maids

⇛250/1500

⇛25/150

⇛1/6

Probability of a family has both type of maids= 1/6.

2⟩ Probability of getting Part time maids

= 860/1500

⇛86/150

⇛43/125

Probability of getting Part time maids = 43/125.

3⟩. Number of part time maids =n(P only )=860

Number of only full time maids =n(F only) = 370

Number of both type of maids = n(PnF)= 250

Total number of families are surveyed= n(PUF)

= 1500

number of no maids =

n(PUF)= n(only P)+n(only F)+n(PnF)

= 1500-(860+370+250)

⇛1500-(1480)

⇛20

Number of no maids = 20

Probability of getting no maid = 20/1500

⇛2/150

⇛1/125

Probability of getting no maid = 1/125.

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5 0

2 years ago