The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Lcm= 2
Because
2/2= 1
2/8=4
2/10=5
Answer:
5.8
Step-by-step explanation:
tangent = opposite over adjacent
10*tan(30) ≈ 5.774
round to the nearest 10th
5.8
if x is changed by 2 , the y changes by +3, Option B is the correct answer.
<h3>What is the equation of a Linear Function ?</h3>
The equation of a Linear Function is given by
y = mx +c
here m is the slope , c is the intercept on the y axis
The data is given in the table
To determine the relation , a function needs to be established between the variables.
m = ( y2 -y1 )/(x2-x1)
m = (-7 +10) /(-2+4)
m = 3 / 2
y = (3/2)x + c
at x = 0 , y= -4
-4 = 0 + c
c = -4
The function is
y = (3/2) x - 4
if x is changed by 2 , the y changes by +3
Therefore Option B is the correct answer.
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Answer:
Step-by-step explanation:
You need to first find what x equals before you can solve the equation.