Answer:
PartA
P = 4a
Part B
60 = P fence + 2a
60 = 6a
Part C
40
Step-by-step explanation:
We are building a fence so we are finding perimeter.
Adding the 3 sides
P = a+b+a
P = 2a+b
It is twice as long as it is wide
b= 2a
Replace in the equation for perimeter
P = 2a+(2a)
P = 4a
Part B
We know the perimeter is 60 for the entire backyard
The perimeter of the backyard is the fence plus the longer side
60 = P fence + b
Replacing b
60 = P fence + 2a
We know the equation for the perimeter of the fence is
60 = 4a + 2a
Combing like terms
60 = 6a
Part C
Solve for a and b
60 = 6a
Divide each side by 6
60/6 = 6a/6
10 =a
P fence = 4a
P = 4(10) = 40
Answer:
0.45
Step-by-step explanation:
Step 1:
Step 2:
8 · x = 0.3 · 12
8x = 3.6
Last Step: Divide both sides by 8 to isolate the value x
2(x + 6) is what you’re looking for. Have a good day!
Note that both scenarios are similar, the only difference is that in scenario 1, the selected card is not returned to the deck and in scenario 2 the card is returned to the original deck.
Therefore, scenario 1 is dependent, since it "depends" on the selected cards before. If on the first attempt you have 13 blacks and 13 reds and you select a red one, then for the second attempt you will have 13 blacks and 12 reds, so this time you will have more chances of getting a black card. Scenario 2 is independent, because when you return the selected card to the deck you will always have 13 red and 13 black cards in each attempt, so each event will be independent of the previous one. Finally, as it was explained above the probability of selecting two red faces are different in each scenario
Vehicle B needs fewer repairs on average but the number of repairs per vehicle has greater variation
