Answer:
Step-by-step explanation:
Where's the problem/question?
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:
60
Step-by-step explanation:
TOTAL SURFACE AREA = AREA OF SQUARE+2×(AREA OF TRIANGLE)
=(6×6)+2×(1/2×6×4)
=36+24=60 square inches
I hope it helped you
Answer
it is 5 : )
Step-by-step explanation:
