Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
<span>Therefore the answer is letter D.</span>
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
<span>Therefore the answer is <span>letter C.</span></span>
Since the data is insufficient. Let us denote that n1 = 100, n2 = 100X1 = 38. X2 = 40
So looking for the p value:
p = (38+ 40) / (100 + 100) = 0.39
z = (38/100 - 40/100)/√ (0.39*(1-0.39)*(1/100 + 1/100))= -0.2899
P-value = P (|z| > 0.2899) = 0.7718
Answer: She is incorrect because 0 + 0 = <u>0</u>
Answer:
See below and image
Step-by-step explanation:
180 + 48 = 228
180 + 55 = 235
Answer:
Step-by-step explanation:
Given
there are six integers to win a lottery
case-1 Integer not exceeding 40
no of ways to choose 6 incorrect numbers
Case-2 no of ways to choose 6 incorrect numbers out of 48 integers
Case-3 no of ways to choose 6 incorrect numbers out of 56 integers
Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers