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postnew [5]
2 years ago
6

I will mark you brainiest if you can answer this

Mathematics
1 answer:
nata0808 [166]2 years ago
6 0
1. C (2,2)
2. H (-9,-5)
3. B (-2,6)
4. E (8,-4)
5. G (-4,-2)
6. ( 6,8)
7. A (-8,4)
8. F (4,-9)
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Let logb A= 3; logb C = 2; logb D=5<br> What is the value of logb D^2/C^3A
Ne4ueva [31]

Answer:

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Step-by-step explanation:

Given as :

Logb A = 3

Logb C = 2

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So,

Logb A = 3 , then A =  b^{3}

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Logb\frac{D^{2}}{C^{3}A}

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log_{b}b = 1

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3 years ago
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