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NISA [10]
2 years ago
9

I need help I don’t lkdkdjxdkdjjddjdjdjd kdkdidjdjrke rikdjekrkdkdj dkdkdkdk

Mathematics
1 answer:
Elena L [17]2 years ago
4 0
Jesse got that as an answer because he only multiples 2X to 2 and not to 8.
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Find the slope for each of the order pair. (-2,-1) and (8,-3)
kondaur [170]

Answer:

-0.2

Step-by-step explanation:

Slope (m) =ΔY/ΔX= 8-(-2)/-3-(-1)

= -1/5

= -0.2

4 0
2 years ago
There are seven cars parked in a row exactly the same distance from each other the first car is 31 inches from the second car th
MakcuM [25]

Answer:

the distance of the 3rd car from the 7th car is

217 inch

8 0
2 years ago
Solve –4(6x + 3) = –12(x + 10). A. x = 2 B. x = 9 C. x = 5 D. x = –5
sergey [27]
–4(6x + 3) = -12<span>(x + 10)
</span><span> -24x - 12 = -12x - 120
12x = 108
x = 9

answer
</span><span>B. x = 9</span><span>

</span>
6 0
3 years ago
How do I solve 1/6 x 2.00=
marysya [2.9K]

Answer:

1/3

Step-by-step explanation:

2= 2/1

1/6 x 2/1

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8 0
2 years ago
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
2 years ago
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