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MatroZZZ [7]
3 years ago
6

The vertex of the graph of a quadratic function is (–2, –9) and the y-intercept is (0, –5). Which of the following is the equati

on of the function?
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

D. On edge

Step-by-step explanation:

allochka39001 [22]3 years ago
5 0
F(x)=a(x-h)^2 + k
f(x)=a(x + 2)^2 - 9
f(0)=5
5=a(0+2)^2 - 9
5=4a-9
4a=14
a= 7/2
f(x)=7/2(x^2 + 4x + 4)-9
=7/2x^2 +14x + 14 - 9
f(x)=3.5x^2 +14x + 5
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In the drawing g>h. which statement about the volumes of the two cylinders is true
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Answer:

The bottom option for ttm

Step-by-step explanation:

The volume of the left-hand cylinder is less than the volume of the right-hand cylinder.

7 0
3 years ago
What is the area of this polygon?​
mash [69]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
What is the equation of the following? Someone could help me to understand this? thank you​
Troyanec [42]

Answer:

y=(1/5)x

Step-by-step explanation:

First, we must find the slope of the line.

The slope of a line can be found using the formula: (y2-y1)/(x2-x1)

(3-0)/(15-0)

(3)/(15)

1/5

The slope is 1/5.

Next we find the y-intercept, or where the line crosses the y-axis. In this case, the y-intercept is 0.

This gives us the equation: y=(1/5)x

Let me know if this helps!

4 0
3 years ago
A nest of ants has been growing exponentially in such a way that its population, P, as a function of w weeks is given by P(w)=24
Hunter-Best [27]

Answer:

0.9%

Step-by-step explanation:

Given that:

A nest of ant is represented by the exponential growth function :

P(w)=24,000(1.063)^w

Where w = number of weeks

Recall :

Growth function is generally represented as :

P(t) = A(1 + r)^t

Where ; A is the initial population figure; r = growth rate and t = time

Hence, the growth rate per week of the function given is :

(1 + r) = 1.063

r = 1.063 - 1

r = 0.063

Number of days in a week = 7

Hence, growth rate per day = r /7

0.063 / 7

= 0.009

(0.009 * 100%) = 0.9%

8 0
3 years ago
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0
2 years ago
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