Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer:
−
6
=
3
7
n
Step-by-step explanation:
Rewrite the equation as
3
7
n
=
−
6
.
3
7
n
=
−
6
Multiply both sides of the equation by
7
3
.
7
3
⋅
3
7
⋅
n
=
7
3
⋅
−
6
Simplify both sides of the equation.
Tap for more steps...
n
=
−
14
Answer:
A overly complicated triangle.
Step-by-step explanation: Good luck...
Answer:
1126.4
Step-by-step explanation:
5.97 x 1024 =6113.28
4.87 x 1024= 4986.88
6113.28-4986.88 =1126.4
Answer: B. 0.25, 3.75, 5.2
Step-by-step explanation:
Since, the given sequence, 
And, 
On substituting n=5 in the given recursive formula,
We get, 
For, n=4 
For, n=3 
For, n=2 
Thus, First second and third terms are,
, 
and 
.
