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3 years ago

Can someone help me with this problem and explain it

Mathematics

2 answers:

enyata [817]3 years ago

4 0

Answer:

A. 30 - y.

Step-by-step explanation:

< GLQ = 180 - 30 = 150.

So < z + <LGQ = 180 - 150 = 30.

< LGQ = < y (opposite angles)

So z + y = 30

So z = 30 - y.

andreev551 [17]3 years ago

4 0

Good evening ,

______

Answer:

z = 30 - y

____________________

Step-by-step explanation:

x=180-30=150

z+x+y=180

Then

z=180-(x+y)

=180-(150+y)

=180-150-y

=(180-150)-y

=30-y.

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Read 2 more answers

A bride and groom both invited guests to their wedding. The bride invited twice as many women as the groom did, and the groom in

n200080 [17]

Answer:

option 1) 50

Step-by-step explanation:

Let m and w denote the men and women respectively.

From the question, if the groom invited w number of women, then bride invited 2w number of women.

Also, if the bride invited m number of men,then the groom invited 2m.

Hence we can write the following maths equation:

w+2m=105.........1

2w+m=135.........2

We multiply eqn(1) by 2 to get eqn(3)

This implies that,

2w+4m=210.......3

We then subtract eqn (2) from eqn(3) to obtain;

3m=75

we divide through by 3

$\implies \frac{3m}{3} = 75$

$\implies m= 25$

Substituting the value of m into eqn (1)

to find the value for w

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subtracting 50 from both sides.

$\implies w + 50 - 50= 105 - 50$

$\implies w+2(25)=105$

$\implies w= 55$

So we can say the :

bride invited 25 men and 110 women,

groom invited 50 men and 55 women.

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