Mallory began the month $135 in debt.
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The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,
The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so
Answer:
Step-by-step explanation:
Given that the probability of a customer arrival at a grocery service counter in any one second is equal to 0.3
Assume that customers arrive in a random stream, so an arrival in any one second is independent of all others.
i.e. X the no of customers arriving is binomial with p = 0.3 and q = 1-0.3 =0.7
a) the probability that the first arrival will occur during the third one-second interval.
= Prob that customer did not arrive in first 2 seconds * prob customer arrive in 3rd sec
=
b) the probability that the first arrival will not occur until at least the third one-second interval.
Prob that customer did not arrive in first two seconds *(Prob customer arrives in 3rd or 4th or 5th.....)
=
The term inside bracket is a geometric infinite progression with common ratio - 0.7 <1
Hence the series converges
Prob =