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3 years ago

1) A triangular prism has a base measuring 8 inches and a side measuring 5

Mathematics

1 answer:

Kruka [31]3 years ago

4 0

Answer:

24 cubic inches

Step-by-step explanation:

Whenever you are finding the volume you have to multiply by two plus a number times two. For example, since there is two depths, you have to multiply 3 by 2 plus the next number. Then, since there is two sides, you multiply 5 by 2 plus the next number. Finally, since there is only one base, you don't have to multiply by two.

(3×2)+(5×2)+8=24

Hope I explained well enough for you to understand.

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!!!!!PLEASE HELP!!!!! *30 POINTS PLEASE*

Lelechka [254]

Answer:

Part 1)

Part a) Yes, triangle ABC is congruent with triangle DEC by SAS

Part b) No, triangle ABC is not congruent with triangle DCE

Part 2) No, is not enough information

Part 3) Yes, triangle RST is congruent with triangle VUT by ASA

Part 4) Yes, triangle DEF is congruent with triangle DHG by SAS

Step-by-step explanation:

Part 1) we have two cases

Part a) Is triangle ABC and DEC congruent?

Yes, triangle ABC is congruent with triangle DEC by SAS

we know that

The Side Angle Side postulate ( SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent

In this problem

AC≅DE

BC≅EC

and

∠ACB≅∠DCE ---> by vertical angles

Part b) Is triangle ABC and DCE congruent?

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

the corresponding sides are not congruent

because

AB is not congruent with DC

Part 2) we have that

No, is not enough information

If AC≅XZ then the triangles ABC and XYZ will be congruent by SSS

If ∠ABC≅∠XYZ then the triangles ABC and XYZ will be congruent by SAS

Part 3) we have that

Yes, triangle RST is congruent with triangle VUT by ASA

we know that

If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle -Side-Angle (ASA) postulate

In this problem

ST≅UT

∠RST≅∠VUT ----> is a right angle

∠RTS≅∠VTU ---->by vertical angles

Two angles and the included side are the same in both triangles

therefore

triangles RST and VUT are congruent by ASA

Part 4) we have that

Yes, triangle DEF is congruent with triangle DHG by SAS

we know that

In this problem

DE≅DH

DF≅DG

and

∠EDF≅∠HDG ---> by vertical angles

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3 years ago

What's the ordered pair ?

nekit [7.7K]

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We clearly see that for ever point in terms of CHOICE C the value of x is different.

Answer: Choice C

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4 years ago

√(6+x-x²)=9 I have to put this just to submit it.

Sergio [31]

We know that it must equal 9, and that we do x•x-x+6 and find the square root

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3 years ago

The coordinates of a triangle are P(1,4). Q(3,6), and R(5,2). The triangle is reflected over a line and its image

Alchen [17]

Answer:

x=0

Step-by-step explanation:

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3 years ago

Solve each quadratic equation by completing the square. Give exact answers--no decimals.

Sholpan [36]

Answer:

$x_1 = -2 + 2i\\\\x_2 = -2 -2i$

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

$7x ^ 2 + 28x +56 = 0$

The steps are shown below:

For any equation of the form: $ax ^ 2 + bx + c = 0$

1. If the coefficient a is different from 1, then take a as a common factor.

In this case $a = 7$ . Then:

$7(x ^ 2 + 4x) = -56$

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is 4. Then, divide by 2 and the result squared it.

We have:

$\frac{4}{2} = 2\\\\(\frac{4}{2})^2 = 4$

3. Add the term obtained in the previous step on both sides of equality, remember to multiply by the common factor $a = 7$ :

$7(x ^ 2 + 4x + 4) = -56 + 7(4)$

4. Factor the resulting expression, and you will get:

$7(x + 2) ^ 2 = -28$

Now solve the equation:

Note that the term $7(x + 2) ^ 2$ is always $> 0$ therefore it can not be equal to -28.

The equation has no solution in real numbers.

In the same way we can find the complex roots:

$7(x+2)^2 = -28\\\\(x+2)^2 = -\frac{28}{7}\\\\x+2 = \sqrt{-\frac{28}{7}}\\\\x = -2 + \sqrt{-4}\\\\x = -2 + 2\sqrt{-1}\\\\x_1 = -2 + 2i\\\\x_2 = -2 -2i$

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4 years ago

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