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kakasveta [241]
2 years ago
7

Gary earns $12 an hour plus $16 an hour for every hour of overtime. Overtime hours are any hours more than 30 hours for the week

. Part A: Create an equation that shows the amount of money earned, M, for working x hours in a week when there is no overtime. (3 points) Part B: Create an equation that shows the amount of wages earned, T, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 30 hours. (3 points) Part C: Gary earned $408 in 1 week. How many hours (regular plus overtime) did he work? Show your work. (4 points)
Mathematics
1 answer:
hoa [83]2 years ago
7 0

Part A.

Amount of money earned = Regular rate per hour * Number of working hours

M = 12 x

 

Part B.

Amount of wages earned = Regular rate per hour * Maximum number of regular working hours + Overtime rate per hour * Excess working hours

T = 12 * 30 + 16 * y

T = 360 + 16 y

or

T = 16 y + 360

 

Part C.

Given T = 408, find y:

408 = 16 y + 360

y = 3 hrs

Therefore the total hours Gary worked that week is,

<span>x + y = 30 + 3 = 33 hrs        </span>

<span>(x = 30 since that is the maximum limit for regular working hours)</span>

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mario62 [17]
(15, -8) :)
From C to midpoint you do (+10, -7), so you have to do that again to get to D
4 0
3 years ago
Which of the following are operations in the algebra of sets?
postnew [5]

Answer:

Union and Intersection

Step-by-step explanation:

We know that the algebra of sets define the properties and laws of the sets.

The basic operations of sets are,

Union, Intersection, Complement of a set and Equality of sets.

Since, the operations addition, subtraction, multiplication and division are the basic arithmetic operations of numbers.

i.e. they are not in the algebra of sets.

So, we get that out of the given options, the operations in algebra of sets are Union and Intersection.

7 0
2 years ago
What is the vertex of a graph
densk [106]
It’s the point where the parabola crosses its axis of symmetry
7 0
3 years ago
Read 2 more answers
Using the Laws of exponents, simplify the following problem.
den301095 [7]
\frac{4 {}^{4} }{ {4}^{ - 8} ({4}^{ - 14}) } = \frac{4 {}^{4} }{ {4}^{ - 22 } }

(4^4)/(4^-22)
4^(4-(-22))
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Follow my Account.
7 0
2 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
2 years ago
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