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Nezavi [6.7K]
4 years ago
8

Solve -4x ≥ -8. Graph the solution.

Mathematics
1 answer:
Semmy [17]4 years ago
7 0

Answer:

do its ??

Step-by-step explanation:

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What is 3 2/5 divided by 1 1/5
creativ13 [48]

Answer:

17/6 or 2 5/6

Step-by-step explanation:

7 0
3 years ago
Describe each of the four major U.S. regions. Focus on facts and details that make each region different or unique.
Fofino [41]
Hey you should copy this and paste it into history.. this is the math section (meaning people trying to answer are less likely to be able to help cus they're here to answer math
8 0
3 years ago
A sticker costs 25 cents. How many dollars is that?
Vera_Pavlovna [14]

Answer:

1/4 of a dollar

Step-by-step explanation:

25x4=100

4 0
3 years ago
Read 2 more answers
2/3x+7=5/6<br> Rewrite the equation below so that it doesn’t have fractions please.
kipiarov [429]

To eliminate all of the fractions in an equation, we can multiply the equation by the least common denominator of all of the fractions in the equation. To find the LCD, we need to find a number that has at least all of the factors of each of the denominators.


To find the LCD of the fractions in this equation, let's look at our denominators, 3 and 6. We can say 3 = 3 and 6 = 2 * 3. By examining this, we can see that our LCD <em>has to have </em>a 3 and 2, since those numbers are found in at least one of the fractions. Thus, our LCD is 3 * 2 = 6.


Now we know to multiply our entire equation by 6. This is solved as shown:

6(\dfrac{2}{3}x + 7) = 6(\dfrac{5}{6}) \Rightarrow \boxed{4x + 42 = 5}


Our answer is 4x + 42 = 5.

5 0
4 years ago
33. Construct a truth table to show that the following argument is valid.
GuDViN [60]

Answer:

  see attached

Step-by-step explanation:

Perhaps you want to show that P∨Q will be equal to Q when ¬P is true. Attached is a truth table that shows this is the case.

__

This is simply a restatement of the logic of the OR function. When one its inputs is a logical 0 (false), the output depends on the other input(s).

5 0
2 years ago
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