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2 years ago

In AOPQ, m2O = (2x – 5)º, m P = (3x – 8)°, and mZQ = (10x – 17). What is the value of x?

Mathematics

1 answer:

Misha Larkins [42]2 years ago

3 0

9514 1404 393

Answer:

x = 14

Step-by-step explanation:

The sum of angles in a triangle is 180°:

∠O +∠P +∠Q = 180°

(2x -5)° +(3x -8)° +(10x -17)° = 180°

15x -30 = 180 . . . . . divide by °, collect terms

x -2 = 12 . . . . . . . . . divide by 15

x = 14 . . . . . . . . . . . .add 2

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Answer:

224 pages total

Step-by-step explanation:

To find how many total pages, you have to multiply the number of sections by the number of pages in each section. 14 sections times 16 pages per section equals a total of 224 total pages.

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3 years ago

Solve by graphing: y=3(x-2)^2-3

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Step-by-step explanation:

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3 years ago

A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI

Vadim26 [7]

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

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4 0

3 years ago

A group of volunteers for a clinical trial consists of 86 women and 79 men. 20 of the women and 21 of the men have high blood pr

Irina18 [472]

Answer:

Dear user,

Answer to your query is provided below

Probability that the person has high blood pressure given that it is a women = (20/41)

Step-by-step explanation:

Total no. Of high blood pressure = 20+21 = 41

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4 0

2 years ago

In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

$y=a(1+r)^{t}$

Here,

y = final value

a = initial value

r = growth rate

t = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of r as follows:

$y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145$

Now, compute the time it will take the population to grow to 800 insects as follows:

$800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17$

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0

3 years ago