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Kryger [21]
3 years ago
7

What is 4x+2/39=5x-2/42?

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
ANSWER: 9/91
EXPLANATION:
4x+2/39=5x-1/21
-x+2/39=-1/21
-x=-9/91
x=9/91
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​ b(1)=−7 b(n)=b(n−1)+12 ​ Find the 4th term in the sequence
forsale [732]

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29




8 0
3 years ago
Read 2 more answers
What is the solution of the equation x − 2 = 29?<br> -31<br> -27<br> 27<br> 31
Allisa [31]

31-2=29 you add 2 to both sides so -2 cancels and you are left with X=31

the answer is 31

5 0
4 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
Please help me I want to finish math homeworkkkkk
Murrr4er [49]

Answer:

39,930 applicants

Step-by-step explanation:

y= 33000(1+.1)^2

y=33000(1.1)^2

y=33000(1.210

y=39930

8 0
4 years ago
Read 2 more answers
2533456534 times 57483939943
Vaselesa [24]
Your answer is:
1.4563306e+20<span>
</span>
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3 years ago
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