All categories

3 years ago

Factor completely (X^2 + x - 6) (2x^2 + 4x) =

Mathematics

1 answer:

Vikki [24]3 years ago

8 0

Answer:

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

Step-by-step explanation:

(X^2 + x - 6) (2x^2 + 4x) =

Let's open the brackets carefully

x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x

= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

You might be interested in

Find the quotient 12÷3/8

bearhunter [10]

Answer:

Step-by-step explanation:

To make it a fraction form answer, you multiply the whole number by the denominator and make the result the new numerator. The old numerator becomes the new denominator

Thus, the answer to 12 divided by 3/8 in fraction form is:

96 /3

To make the answer to 12 divided by 3/8 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

96 / 3 = 32

The answer is rounded to the nearest two decimal points if necessary.

96/3 can be simplified to 32/1.

32/1 is an improper fraction and should be written as 32.

Hope this helps <3

3 0

2 years ago

Read 2 more answers

The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,

max2010maxim [7]

Answer:

This was in 2019 hope they solved it..

Step-by-step explanation:

5 0

3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

If the coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6), the x-intercept of is . Point lies on .

solmaris [256]

You would move five down and eight to the right, it depends how how the grid is

4 0

3 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago