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cricket20 [7]
3 years ago
11

Which of the following sets of numbers is not a Pythagorean triple?

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

10,15,20

Step-by-step explanation:

Pythagorean triple is when three number satisfies a^{2} +b^{2} =c^{2}.

For  3,4,5

if a=3, b=4 and c=5

then

(3)^{2} +(4)^{2} =(5)^{2}

9 +16 =25

25 =25

The left hand and right hand side are satiesfied.

So, the numbers 3,4,5 are Pythagorean triple.

For  10,15,20

if a=10, b=15 and c=20

then

(10)^{2} +(15)^{2} =(20)^{2}

100 +225 =400

325\neq400

The left hand and right hand side are not satiesfied.

So, the numbers 10,15,20 are not Pythagorean triple.

Hence, we get the set of numbers which are not Pythagorean triple that is <u>10,15,20.</u>

leonid [27]3 years ago
4 0
10 15 20 since i am pretty sure the rest are a triple(definitely 3 4 5 and 7 24 25 is a triple0 
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Solve.<br> (2x+24)(4x+36)
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A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

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The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

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Download pdf
8 0
3 years ago
If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

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