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2 years ago

I need this done today whoever gets this correct gets brainliest!!! PLZZ HELPP MEE!!! hurryy

Mathematics

2 answers:

bearhunter [10]2 years ago

5 0

Answer:

A (I carefully did it)

Step-by-step explanation:

This is a really easy algebra question tho

1. Step 1 -> Step 2 is wrong

2. Step 1:

$0.2(4+1.4y-2.1)=0.8+0.28y-0.42$

3. But Step 2:

$0.2(4+1.4y-2.1)\neq 4.2+1.6y-1.9$

4. She added 0.2 to each term instead of multiplying by 0.2

nikdorinn [45]2 years ago

4 0

Answer:

Step-by-step explanation:

This is a really easy algebra question tho

1. Step 1 -> Step 2 is wrong

2. Step 1:

3. But Step 2:

4. She added 0.2 to each term instead of multiplying by 0.2

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A pair of shoes is on sale for 15% off. With this discount, customers will save $9 if they buy the shoes. Part AIn this situatio

In-s [12.5K]

Answer:

(b)The original price of the shoes is $60.

Explanation:

Part A

In this situation:

• 15% is the PERCENT

• $9 is the PART

• The original price is the WHOLE.

Part B

If 15% is taken off, the customer will save $9.

This means that 15% of the original price = $9.

Let the original price=p

$\begin{gathered} 15\%\text{ of p=9} \\ \frac{15}{100}p=9 \\ 15p=900 \\ p=\frac{900}{15} \\ p=60 \end{gathered}$

The original price of the shoes is $60.

8 0

1 year ago

2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.

igomit [66]

The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon

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2 years ago

Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit

adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

$H_0:$ There's no variation among the discussion sections

$H_1:$ There's variation among the discussion sections

$\alpha =0.05$

Df Sum Sq Mean sq F value Pr(>F)

Section 7 525.01 75 1.87 0.99986

Residuals 189 7584.11 40.13

Test Statistic = $F= \frac{75}{40.13} =1.87$

$Pr(>F) = 0.99986$

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

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2 years ago

Jerod delivers pizzas part-time. Last year he drove 4071 miles. This year he drove 5103 miles. How many more miles did he drive

poizon [28]

Answer:

1032 miles

Step-by-step explanation:

We have : 5103 - 4071 = 1032(miles)

So he drove more 1032 miles this year than last year

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2 years ago

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