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3 years ago

Can u help me with my work pls

Mathematics

2 answers:

ella [17]3 years ago

6 0

Answer:

The mountain is 8.

The map is 96.

The compass is 6.

The hiker is 54.

The train is 14.

The a corn is 26

Hope this helps.

Rasek [7]3 years ago

3 0

36-4=32/4=8

24+24=48

48/16=3

4(9)=36

20-15=5

31-12=19

Trees=8
Map=48
Compass=3
Hiker=36
Backpack=5
Acorn=19

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Divide 8 1/8 by 7 1/12 simplify the answer and write as a mixed number

vladimir1956 [14]

The division of 8 1/8 by 7 1/12 is 91/136.

<h3>What is division?</h3>

Division simply has to do with reduction of a number into different parts. On the other hand, a mixed number is the number that's made up of whole number and fraction.

Dividing 8 1/8 by 7 1/12 will go thus:

8 1/8 ÷ 7 1/12

Change to improper fraction

65/8 ÷ 85/7

= 65/8 × 7/85

= 91/136

The division will give a value of 91/136.

Learn more about division on:

brainly.com/question/25289437

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1 year ago

Tell whether a triangle can have sides with the

Dmitry [639]

Answer:

$3x+2 \ne x^2 \ne 2x$ for $x = 4$

Step-by-step explanation:

Given

Shape: Triangle

Dimension: 3x + 2, x^2 and 2x

$x = 4$

Required

Determine if it has equal sides

To do this, we simply substitute 4 for x in the given dimensions

3x + 2

$3x + 2 = 3 * 4 + 2$

$3x + 2 = 12 + 2$

$3x + 2 = 14$

x^2

$x^2 = 4^2$

$x^2 = 16$

2x

$2x = 2 * 4$

$2x = 8$

$3x+2 \ne x^2 \ne 2x$ for $x = 4$

8 0

3 years ago

HELP!!!!!! Define each of the following: Population Random sample Inference

swat32

Answer:

Population amount of people

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Step-by-step explanation:

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3 years ago

Solve the matrix and prove that it is equal 0

Art [367]

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

$\tt{ {A}^{T} = \begin{bmatrix} 2 & - 4 \\ 4 & 3 \\ \end{bmatrix}}$

$\underline{ \underline { \text{To \: Find}}} :$

$\sf{ {A}^{2} - 5A+ 22I= 0}$

$\underline{ \underline{ \text{Solution}}} :$

The new matrix obtained from a given matrix by interchanging it's rows and columns is called the transposition of matrix. It is denoted by $\sf{ {A}^{T}}$ . Again , Interchange it's rows and columns in order to find ' A '.

$\tt{A = \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix}}$

Now , LEFT HAND SIDE ( L.H.S )

$\tt{ {A}^{2} - 5A+ 22I}$

Here, I refers to identity matrix. A diagonal matrix in which all the elements of leading diagonal are 1 ( unit ) is called unit or identity matrix.

⟼ $\begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} \times \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} - 5 \times \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} + 22 \times \begin{bmatrix} 1 & 0 \\ 0 & 1\\ \end{bmatrix}$

⟼ $\begin{bmatrix} 2 \times 2 + 4 \times ( - 4)& 2 \times 4 + 4 \times 3 \\ - 4 \times 2 + 3 \times ( - 4) & - 4 \times 4 + 3 \times 3 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20& 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$

⟼ $\begin{bmatrix} 4 + ( - 16) & 8 + 12 \\ - 8 + ( - 12) & - 16 + 9 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$

⟼ $\begin{bmatrix} - 12 & 20\\ - 20& - 7 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$