I'm assuming that you mean

because if you meant

then u would simplify and you couldn't make it the subject.
Under this assumption, we start with

We multiply both sides by 

We expand the left hand side:

We move all terms involving u to the left and all terms not involving u to the right:

We factor u on the left hand side:

We divide both sides by 

Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
Answer:
D
Step-by-step explanation:
Given the quadratic
d = - 16t² + 12t ← subtract d from both sides
- 16t² + 12t - d = 0 ← in standard form
with a = - 16, b = 12, c = - d
Use the quadratic formula to solve for t
t = ( - 12 ±
) / - 32
= ( - 12 ±
) / - 32
= ( - 12 ±
) / - 32
= ( - 12 ± 4
) / - 32
=
± 

=
± 

=
±
→ D
Factor out 3x
Answer: 3x(x - 5)
Answer:
(c) 112 ft/sec
Step-by-step explanation:
4 = 112.33 ft/sec = 112 ft/sec