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Virty [35]
2 years ago
12

Write 95% as a fraction in simplest form

Mathematics
2 answers:
soldier1979 [14.2K]2 years ago
8 0

\huge\textsf{Hey there!}

\large\text{95\% as a fraction}

\large\text{We know percentages runs out of 100, so we first divide 95} \\\large\text{from 100 and answer that one to actually solve for your answer}

\mathsf{\dfrac{95}{100}}

\boxed{\mathsf{= \bf 0.95}}\large\checkmark

\mathsf{\dfrac{0.95}{1}\times\dfrac{100}{100}}

\large\text{CROSS MULTIPLY}

\mathsf{\dfrac{0.95\times100\leftarrow \bold{numerator}}{1\times100\leftarrow \bold{denominator}}}}

\mathsf{0.95\times100 = \boxed{\bf 95}}\large\checkmark

\mathsf{1\times100=\boxed{\bf 100}}\large\checkmark

\large\text{NEW EQUATION: }\mathsf{\dfrac{95}{100}}

\large\text{FINALLY we simplify the fraction}

\large\text{Each of your numbers are factors of 5, so we divide both numbers by 5}

\mathsf{\dfrac{95\div5}{100\div5}}

\mathsf{95\div 5 = \boxed{\bf 19}\large\checkmark\leftarrow \underline{numerator}}

\mathsf{100\div5 = \boxed{\bf 20}\large\checkmark\leftarrow \underline{denominator}}

\boxed{= \mathsf{\bf\dfrac{19}{20}}}\huge\checkmark

\boxed{\boxed{\huge\textsf{Answer: }\mathsf{\bf \dfrac{19}{20}}}} \huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

Mice21 [21]2 years ago
6 0

Answer:

19/20

Step-by-step explanation:

95%/100=0.95

=95/100

simplified

19/20

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Answer:

−6a − 35b + 48c

Step-by-step explanation:

You do pemdas and if you know Pemads you will get your anwser

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A rectangle is to be inscribed in an isosceles right triangle in such a way that one vertex of the rectangle is the intersection
svet-max [94.6K]

Answer:

x  =  2  cm

y  = 2  cm

A(max) =  4 cm²

Step-by-step explanation: See Annex

The right isosceles triangle has two 45° angles and the right angle.

tan 45°  =  1  =  x / 4 - y        or     x  =  4  -  y     y  =  4  -  x

A(r)  =  x* y

Area of the rectangle as a function of x

A(x)  =  x  *  (  4  -  x )       A(x)  =  4*x  -  x²

Tacking derivatives on both sides of the equation:

A´(x)  =  4 - 2*x             A´(x)  =  0            4   -  2*x  =  0

2*x  =  4

x  =  2  cm

And  y  =  4  - 2  =  2  cm

The rectangle of maximum area result to be a square of side 2 cm

A(max)  = 2*2  =  4 cm²

To find out if A(x) has a maximum in the point  x  =  2

We get the second derivative

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5 0
2 years ago
Select ALL the correct answers.
stiv31 [10]

Answer:

Statements 3, 4 and 5 are true.

Step-by-step explanation:

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Using the quadratic formula:

x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2

= (8 +/- √(64 - 16)) / 2

= 4 +/- √48 / 2

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= 4 +/- 2√3.

So the third statement is true.

Converting to vertex form:

x^2 - 8x + 4

= (x - 4)^2 - 16 + 4

= (x - 4)^2 -12

So the extreme value is at (4, -12)

So the fourth statement is true.

The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.

4 0
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