For loop, if you have to fill water in a bucket three times, It will fill water in a bucket three times. While loop, If you have to take water from the well multiple times but stop when the water is empty in the well.
Explanation:
- For loop is used mostly static way of programming.
- While loop is used for dynamic approach of programming.
- Static approach has fix number of times the task is done.
- Dynamic approach is conditional attempt to complete the entire task.
- For loop uses discrete which means it uses the count approach.
- While loop is basis on characteristic, It works mostly with alphabet.
- Functions play major role in while loop to take a dynamic approach.
Answer:python
Explanation:
it’s a good coding program
Answer:
switchboard
Explanation:
The option that he should implement would be a switchboard interface design. These design structures for graphic user interfaces use a single main page, large icons/buttons, a fixed navigation menu, and all the necessary functionality right in front of the user. This design is made with simplicity in mind in order to make it as easy as possible for a new user to pick up and efficiently and intuitively navigate the user interface. Therefore, since Calvin needs a simple yet professional design, this would be the best implementation.
<span>According to the Doppler effect, objects moving away from Earth would have a redshift. </span>A <span> redshift means that every wavelength becomes longer and if we observe Hydrogen lines that are at a certain position, those will become redshifted.</span>
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
