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3 years ago

Factor : 2b^2 + 13b - 7Please help !!! :)

Mathematics

1 answer:

julsineya [31]3 years ago

4 0

2b² + 13b - 7

First you multiply the first and last number together, which is 2 and 7.

2 · 7 = 14

Now that you got 14, you try to find all the factors of 14 and see if any of them add up to or subtract to 13.

14:

1 · 14 = 14

2 · 7 = 14

Your factors are 1, 2, 7, and 14. 14 and 1 subtract to 13, so you can replace 13b with this:

2b² + 14b - 1b - 7 (it is not -14b + 1b because 13b is positive)

Next you factor the equation separately.

2b(b + 7) - 1b - 7

2b(b + 7) - 1(b + 7)

(2b - 1)(b + 7)

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romanna [79]

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Step-by-step explanation:

8 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

Suppose that $2000 is invested at a rate of 2.6% , compounded semiannually. Assuming that no withdrawals are made, find the tota

EleoNora [17]

Answer:

$2,589.52

Step-by-step explanation:

$A = P(1 + \dfrac{r}{n})^{nt}$

We start with the compound interest formula above, where

A = future value

P = principal amount invested

r = annual rate of interest written as a decimal

n = number of times interest is compound per year

t = number of years

For this problem, we have

P = 2000

r = 0.026

n = 2

t = 10,

and we find A.

$A = $2000(1 + \dfrac{0.026}{2})^{2 \times 10}$

$A = $2589.52$

8 0

3 years ago

Read 2 more answers

Which of the following describes the translation of the graph of y = x2 to obtain the graph of y = -x2 - 3?

Ray Of Light [21]

Answer:

reflections across the x axis and a shift down 3 units

Step-by-step explanation:

y = x^2

The negative sign means it is a reflection across the x axis y = −f(x)

y = -x^2

The subtraction of 3 means we are shifting down 3 units

y = -x^2 -3

5 0

3 years ago

A. Complete the table if y varies

serious [3.7K]

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

y = 30

y = 30 k = 6

y = 30 k = 6x = 5

y = 30 k = 6x = 5Equation: y = 6x

y = k × x

y = 10 × 8

y = 80

So,

y = 80

y = 80 k = 10

y = 80 k = 10x = 8

y = 80 k = 10x = 8Equation: y = 10x

y = 3x

18 = 3x

x = 18/3

x = 6

So,

y = 18

y = 18k = 3

y = 18k = 3x = 6

y = 18k = 3x = 6Equation: y = 3x

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

y = 72

y = 72k = 2

y = 72k = 2x = 6

y = 72k = 2x = 6Equation: y = 2x²

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

y = 5

y = 5k = 30

y = 5k = 30x = 6

y = 5k = 30x = 6Equation: y = 30/x

y = k/x

y = 36/4

y = 9

So,

y = 9

y = 9k = 36

y = 9k = 36x = 4

y = 9k = 36x = 4Equation: y = 36/x

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

y = 20

y = 20k = 60

y = 20k = 60x = 3

y = 20k = 60x = 3Equation: y = 60/x

y = 24/x

y = 24/12

y = 2

So,

y = 2

y = 2k = 24

y = 2k = 24x = 12

y = 2k = 24x = 12Equation: y = 24/x

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3 0

2 years ago