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elena55 [62]
3 years ago
14

According to the graph on your graphing tool, what is true about f(x)= x^4-4x^2+x/-2x^4+18x^2

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Answer:

I can't see the options, so i will find all the asymptotes.

We have the function:

f(x) = \frac{x^4 - 4*x^2 + x}{-2*x^4 + 18*x^2}

First, we can graph this using a graphing tool, the graph can be seen below.

In the graph, we can see that when we approach x = 0 from the left, f(x) goes to negative infinity, while if we approach x = 0 from the right, f(x) goes to infinity.

This can be written as:

\lim_{x \to 0_-} f(x) = - \infty \\

and:

\lim_{x \to 0_+} f(x) = + \infty \\

A similar thing can be seen at x = 3, when we approach from the left f(x) goes to infinity, while if we approach from the left, f(x) goes to negative infinity.

Then:

\lim_{x \to 3_-} f(x) =  \infty \\\\\lim_{x \to 3_+} f(x) = - \infty \\

For x = -3 we can see that when we approach from the left, f(x) goes to negative infinity, while if we approach from the right, f(x) goes to infinity.

Then:

\lim_{x \to -3_-} f(x) = - \infty \\\\\lim_{x \to -3_+} f(x) = + \infty \\

We also can see that as x goes to negative infinity or positive infinity, f(x) tends to -0.5

Then:

\lim_{x \to \infty} f(x) = -0.5 \\ \lim_{x \to -\infty} f(x) = -0.5

So you need to check the options that match with some of the given tendencies.

maria [59]3 years ago
8 0

Answer:

b,c,d

Step-by-step explanation:

edg 21 ^u^

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Each person in random samples of 207 male and 253 female working adults living in a certain town in Canada was asked how long, i
Sergeu [11.5K]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females (P-value=0.155).

Step-by-step explanation:

The data is:

Males n1=207 M1=31.6 s1=24.0

Females n2=253 M2=29.3 s2=24.3

This is a hypothesis test for the difference between populations means.

The claim is that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

Then, the null and alternative hypothesis are:

H_0: \mu_m-\mu_f=0\\\\H_a:\mu_m-\mu_f> 0

The significance level is 0.05.

The sample 1 (males), of size n1=207 has a mean of 31.6 and a standard deviation of 24.

The sample 2 (females), of size n2=253 has a mean of 29.3 and a standard deviation of 24.3.

The difference between sample means is Md=2.3.

M_d=M_m-M_f=31.6-29.3=2.3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{24^2}{207}+\dfrac{24.3^2}{253}}\\\\\\s_{M_d}=\sqrt{2.783+2.334}=\sqrt{5.117}=2.262

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_m-\mu_f)}{s_{M_d}}=\dfrac{2.3-0}{2.262}=\dfrac{2.3}{2.262}=1.017

The degrees of freedom for this test are:

df=n_1+n_2-1=207+253-2=458

This test is a right-tailed test, with 458 degrees of freedom and t=1.017, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.017)=0.155

As the P-value (0.155) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

7 0
3 years ago
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