Question

Please find x! Thank you, only if you know!

Answer 1

Answer:

$\boxed {\boxed {\sf x \approx 23.49 \ cm }}$

Step-by-step explanation:

This is a right triangle (the small square in the corner signifies a 90 degree angle), so Pythagorean Theorem can be used.

$a^{2} + b^{2} =c^{2}$

where a and b are the legs of the triangle and c is the hypotenuse. In this triangle, 17 and x are the legs because they form the right angle. 29 in the hypotenuse because it is opposite the right angle.

$a= 17 \\b=x \\c= 29$

$17^{2} + x^{2} =29^{2}$

Solve the exponents.

• 17²=17*17=289
• 29²= 29*29=841

$289+x^{2} =841$

289 is being added to x and the inverse is subtraction. Subtract 289 from both sides to isolate the variable.

$289-289+ x^{2} =841-289\\x^{2} =552$

x is being squared and the inverse is a square root. Take the square root of both sides of the equation.

$\sqrt {x^{2} }=\sqrt {552}$

$x=23.4946802489$

Let's round to the nearest hundredth. The 4 in the thousandth place tells us to leave the 9.

$x \approx 23.49$

x is approximately 23.49 centimeters.