Both A. and D. are increasing.
Answer:
The nth term of the given sequence

Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given sequence -5,-4,-1,4,11,20,31
a₀ = -5
a₁ = a₀ +1 = -5 +1 = -4
a₂ = a₁ + 3 = -4+3 = -1
a₃ = a₂ + 5 = -1 +5 = 4
a₄ = a₃ + 7 = 4 + 7 =11
a₅ = a₄ + 9 = 11+9 = 20
a₆ = a₅ + 11 = 20+11 = 31
a₇ = a₆ + 13 = 31 +13 =44
and so on
The nth term of the given sequence

An=a1r^(n-1)
given
a5=1/24
a10=1/768
we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)
so
1/24=a1r^4
1/768=a1r^9
(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32
r^5=1/32
take 5th root of both sides
r=1/2
we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3
the first term is 2/3
Answer:
2/21 times 7/5 is 14/105.
Step-by-step explanation:
2 • 7 = 14 Multiply the numerators
21 • 5 = 105 Multiply the denominators
14/105
Hope this helps,
♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥