Answer:
Autotrophic yes multicellular
Heterotrophic yes multicellular
Explanation:
Answer:
1. Another word for chemical weathering is b. disintegration
Chemical weathering is a process by which the rocks are broken down into parts and sediments by the action of a chemical agent such as alkali or acid. The disintegration can be a natural process by which a solid body is broken down into parts or subparts.
2. d. moving water is not an agent of chemical weathering agent.
The chemical weathering can be caused by the agents like lichens which secretes acid on the rock surface and causes it's disintegration, acid rain and salt water are chemical agents that can cause the disintegration of the rock but moving water will have little influence on the hard rock surface.
3. c. chemical weathering is a process which turns rocks and minerals into new substances. The chemical weathering process brings change in the chemical composition of the rocks due to the action of the weathering agents hence, on disintegration of rocks new substances are formed.
Answer:
Generally, the Earth is divided into spheres which include the "lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air). The earth is divided into three layers based on chemical composition and these are the core, mantle and crust. In addition, the earth is also divided into physical properties which include lithosphere, athenosphere, mesosphere, outer core and inner core. Based on the given details, we can conclude that the atmosphere cannot be part of the lithosphere but instead, it is classified in a separate layer. The lithosphere only consists the outermost, rigid part of the Earth, which are the crust and the mantle. Hope this answer helps
Explanation:
Start with the one that you know better the beginning of essays are hakf the tine awkward anyway.
Answer:
Explanation:
Bacterial count in stock- 1.85x10^6 cfu/ml
Dilution methods
Take 100 uL or (0.1ml) from stock and add to 900ul (0.9ml) saline and mixed it- this makes 10^1dilution.
Now take 100ul from 10^1 dilution and add to next 900ul saline this is 10^2 dilution, similarly do upto 10^5 dilution.
Then take 100ul from 10^ 4 and 10^5 dilution seperately and plate on LB agar plate seperetely and count the colonies.
Cfu/ml formula= (No.of colonies x dilution factor)/0.1 ml
So suppose, 18 colonies formed on 10^4 dilution then total no. Of cells in stock will be 18x10^4/ 0.1= 18x10^5 cfu/ml.
If we dilute 10^4 or 10^5 that's leads to colony count of 18-19 colonies on 10^4 dilution while 2 colonies should come on plate of 10^5 dilution.
