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dedylja [7]
3 years ago
14

Which is most likely to promote the growth of animals?

Biology
1 answer:
kenny6666 [7]3 years ago
6 0
What is the choices ???????
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PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
-Dominant- [34]
That sucks for you sorry that this doesn’t help you
6 0
3 years ago
The disease bullous pemphigoid results in the destruction of proteins within the basement membrane that holds the epidermis and
SVETLANKA909090 [29]
This would directly affect the epidermis because blisters will develop within the surface of the skin. Having blisters on the epidermis will decrease the function of the skin to be an effective barrier to disease. This is because blisters are open wounds that are prone to infection. As infection passes through these openings, it will affect the dermis and the other layers of the skin. Bullae is actually an auto-immune skin disease.
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3 years ago
Assume that you have an illuminated suspension of Chlorella cells carrying out photosynthesis in the presence of 0.1% carbon dio
goldenfox [79]

Answer:

a. PGA down, RuBP up

Explanation:

RuBP, also known as Ribulose-1,5-bisphosphate is a molecule that assist in he fixation of carbon dioxide in the Calvin Cycle or light independent reaction of photosynthesis.

RuBP is combined with carbon dioxide using the enzyme known as rubisco to form an short-lived intermediate product which divides to form two 3-carbon molecule structure known as 3-phosphoglycerate.

<em>If the concentration of carbon dioxide is suddenly reduced, it thus means that the rate of production of 3-phosphoglycerate will reduce as carbon dioxide becomes a limiting factor. Hence, 3-phosphoglycerate's  concentration will reduce while more RuBP will become available as a result.</em>

The correct option is a.

3 0
3 years ago
PLEASE ANSWER THIS QUESTION!!!!
luda_lava [24]

Answer:

A

Explanation:

During prophase I, the homologous chromosomes condense and become visible as the x shape we know, pair up to form a tetrad, and exchange genetic material by crossing over.

8 0
2 years ago
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4. Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If t
lisov135 [29]

Answer:

The correct answer would be:

  • Genotype ratio: 1 (PP) : 2 (Pp) : 1 (pp)
  • Phenotypic ratio: 3 (polka-dot tails) : solid colored tail

The genotype of both parents is Pp (heterozygous).

Thus, both the parent would produce two types of gametes which are P and p.

The cross would result in the production of offspring with three types of genotype PP, Pp, and pp in 1:2:1.

Offspring with PP and Pp will have a polka-dotted tail as it is the dominant trait.

Thus, the phenotype ratio would be 3 (polka-dotted tail) : 1 (solid colored tail).

3 0
3 years ago
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