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Sergeu [11.5K]
2 years ago
11

Someone help me please

Mathematics
1 answer:
Orlov [11]2 years ago
5 0

Answer:

A 500.00 look there's a pattern

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2x^3-3x^2-11x+6 divide by x-3
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Answer: 2x^2+3x-2

Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

Your final step is to do \frac{-2x}{x} =-2. Write this -2 next to your other two parts

Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

2x^2+3x-2 times

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F(x) = (4x–5)/6 <br> Find the Inverse
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Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

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Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps!  Stay Safe!

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